EE 205

Questions and Answers

This page includes questions from ee205 students and the responses from the instructor.

Q: What exactly is the course mailing list for? Is it to post our grades for the entire class to see? Is it for class announcements? I have never done this in a class before, so I would like to know what I would be getting myself into.

The mailing list is for class announcements from the instructor and for students in the class to communicate with each other. I will never post grades to the list. There is a risk that if it is popular, you will be getting a lot of e-mail from other students in the class. Since I am also on the list, I will make sure there aren't many postings that do not pertain to the course.

Q: What's up with example ___, I just can't seem to get the same answers?

There are typo's in the book, so be ware and sorry about that.

Q: Is there a way to get the solutions posted on the web so that we can print out copies of the solutions?

As noted in the syllabus, the solutions for all assigned problems are available in the main office (front desk in Dreese Labs 205). As for posting them on the web, I want to engage your mind as you look over the solutions. Although it is inconvenient to come in, I feel that you will learn a lot more by hand than you will by printing.

Q: So what's the deal with current through voltage sources? While we're at it, voltage through current sources?

A: When in doubt, fall back on the i-v relationships. Current source: i is dictated by the source, v is unknown (i.e., it can be anything, as dictated by the circuit); voltage source: i is unknown, v is dictated by the source; resistor: v=iR (note how there is no "R" for the ideal sources). While on the subject, two sources in series will be additive. E.g., for voltage sources using KVL, you will see the first voltage rise (or drop) and then the next voltage rise (or drop). Also note that sources with opposing orientations will (partially) cancel each other out.

Q: If I only know the current on one side of a two terminal device, how do I find the current on the other?

A: Current is the flow of charge, since we are only working with two terminal devices, what goes in must come out. So what does this mean for serially connected devices? The same current flows through all of them. But without further analysis, we don't know what happens with the voltage. On the other hand, for devices connected in parallel, the same voltage is present across each of them, but the individual currents flowing through them are unknown. These two examples are analogs, switch "voltage" with "current", then switch "parallel" with "serial" and you have the same statement. KCL can be generalized to regions, not just nodes. So the serial example is simply KCL applied to a region that has two i/o lines and multiple devices.